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JAMB Physics 2013 Paper

Question : 10

Total: 43

Calculate the work done when a force of 20N stretches a spring by 50mm.

Solution:

Concept:

For stretching a spring, the work done is the elastic potential energy stored, calculated from

W = \frac{1}{2} F e

, where

F

is the applied force and

e

is the extension.

Explanation:

First, convert the extension from millimetres to metres so the units match.

50\text{ mm} = \frac{50}{1000} = 0.05\text{ m}

Use the formula for work done on a spring:

W = \frac{1}{2} F e

Substitute the given values:

W = \frac{1}{2} \times 20 \times 0.05

W = 0.5\text{ J}

Answer:

The work done is

0.5\text{ J}

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