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JAMB Physics 2012 Paper

Question : 21

Total: 42

Solution:

Concept:

Compare the given wave equation with the standard travelling wave equation.

Explanation:

The standard wave equation is

y = A\sin\left(\frac{2\pi}{\lambda}(vt - x)\right)

The given wave equation is

y = 15\sin\left(\frac{2\pi}{5}(60t - x)\right)

When compared, the coefficient multiplying

(60t - x)

gives:

\frac{2\pi}{\lambda} = \frac{2\pi}{5}

Cancel

2\pi

from both sides.

Therefore,

\lambda = 5

Answer:

\lambda = 5

m, so the correct option is C.

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