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JAMB Physics 2011 Paper

Question : 7

Total: 44

[g = 10 ms²]

Solution:

Concept:

Upthrust equals the apparent loss of weight of an object when immersed in a liquid.

Explanation:

Weight in air is

30 \, \text{kg} \times 10 \, \text{m/s}^2 = 300 \, \text{N}

Weight in water is

22 \, \text{kg} \times 10 \, \text{m/s}^2 = 220 \, \text{N}

The upthrust is the difference between these two weights:

\text{Upthrust} = 300 \, \text{N} - 220 \, \text{N} = 80 \, \text{N}

This loss of weight is the buoyant force exerted by the liquid on the object.

Answer:

The upthrust exerted by the liquid is

80 \, \text{N}

, which is option D.

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