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JAMB Physics 2011 Paper

Question : 36

Total: 44

A radioactive isotope has a decay constant of 10-5s4. Calculate half life

Solution:

Concept:

Half-life is the time for half of a radioactive sample to decay.

It is inversely proportional to the decay constant

\lambda

Explanation:

The half-life formula is:

T_{1/2} = \frac{0.693}{\lambda}

Given decay constant:

\lambda = 10^{-5} \, \text{s}^{-1}

Substitute into the formula:

T_{1/2} = \frac{0.693}{10^{-5}}

This gives:

T_{1/2} = 0.693 \times 10^5

T_{1/2} = 6.93 \times 10^4 \, \text{s}

Answer:

6.93 \times 10^4 \, \text{s}

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