Test Index

JAMB Physics 2011 Paper

Question : 18

Total: 44

[velocity of sound in the air = 330 ms-1]

Solution:

Concept:

The time for sound to travel a distance is found using the relation between distance, speed, and time.

Explanation:

Convert the distance from kilometres to metres:

4.95\text{ km} = 4.95 \times 10^3\text{ m} = 4950\text{ m}

Use the formula

v = \dfrac{d}{t}

, where

v = 330\text{ m s}^{-1}

and

d = 4950\text{ m}

Rearrange to solve for time:

t = \dfrac{d}{v} = \dfrac{4950}{330}

t = 15\text{ s}

Answer:

The sound is heard after

15\text{ s}

. Therefore, the correct option is D.

Go to Question:

Prev Question

Next Question