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JAMB Physics 2010 Paper

Question : 41

Total: 47

Solution:

Concept:

The total opposition to current flow in a circuit consists of both the external resistance and the internal resistance of the cell.

Explanation:

For a cell with e.m.f

E

, internal resistance

r

, and external resistance

R

, the current

I

is given by

I = \frac{E}{R + r}

Here,

E = 12\ \mathrm{V}

R = 2\ \Omega

, and

r = 4\ \Omega

Total resistance

R + r = 2 + 4 = 6\ \Omega

Therefore,

I = \frac{12}{6} = 2\ \mathrm{A}

Answer:

I = 2\ \mathrm{A}

, which is option D.

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