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JAMB Physics 2010 Paper

Question : 16

Total: 47

[molar gas constant = 8.3 J mol-1 k-1]

Solution:

Concept:

Use the ideal gas equation

PV = nRT

to find the pressure when

n

V

, and

T

are known.

Explanation:

First, convert the temperature from Celsius to Kelvin.

T = 27 + 273 = 300 \, \text{K}

The number of moles is

n = 1

Volume is

V = 10^{-2} \, \text{m}^3

Molar gas constant is

R = 8.3 \, \text{J mol}^{-1} \text{K}^{-1}

From

PV = nRT

, solve for pressure

P

P = \frac{nRT}{V} = \frac{1 \times 8.3 \times 300}{10^{-2}}

P = \frac{2490}{10^{-2}} = 249000 \, \text{N m}^{-2}

So,

P = 2.49 \times 10^5 \, \text{N m}^{-2}

Answer:

The correct option is

2.49 \times 10^5 \, \text{N m}^{-2}

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