Make q the subject of the relation t = {pq/r - r²q}

Correct Answer is : q = rt2p−r3{rt²}{p - r³}p−r3rt2

Correct Answer is : q = rt2p−r3{rt²}{p - r³}p−r3rt2

Test Index

JAMB Mathematics 2024 Paper

Question : 49

Total: 50

\sqrt{\frac{pq}{r} - r^{2}q}

Solution:

Concept:

Make

q

the subject by removing the square root and isolating

q

using algebraic operations.

Explanation:

Start with the relation:

t = \sqrt{\frac{pq}{r} - r^{2}q}

Square both sides to eliminate the square root:

t^{2} = \frac{pq}{r} - r^{2}q

Factor

q

out of the expression on the right:

t^{2} = q\left(\frac{p}{r} - r^{2}\right)

Write the bracket as a single fraction with denominator

r

\frac{p}{r} - r^{2} = \frac{p - r^{3}}{r}

So:

t^{2} = q\left(\frac{p - r^{3}}{r}\right)

Multiply both sides by

r

rt^{2} = q(p - r^{3})

Divide both sides by

(p - r^{3})

q = \frac{rt^{2}}{p - r^{3}}

Answer:

q = \frac{rt^{2}}{p - r^{3}}

This is option A.

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