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JAMB Mathematics 2024 Paper

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Question : 36

Total: 50

From a class of 5 girls and 7 boys, a committee consisting of 2 girls and 3 boys is to be formed. How many ways can this be done?

350 ways
420 ways
550 ways
720 ways

Solution:

Concept:

Selection without order is done using combinations.

Explanation:

Choose 2 girls from 5:

\binom{5}{2} = \frac{5!}{2!(5-2)!} = \frac{5 \times 4}{2 \times 1} = 10

.

Choose 3 boys from 7:

\binom{7}{3} = \frac{7!}{3!(7-3)!} = \frac{7 \times 6 \times 5}{3 \times 2 \times 1} = 35

.

Multiply the two independent choices to get the total number of committees.

Total

= 10 \times 35 = 350

.

Answer:

A. 350 ways

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