JAMB Mathematics 2024 Paper

Concept:The graph shows the region of points that satisfy a set of linear inequalities in the first quadrant.Explanation:The boundary line passes through $(4, 0)$ and $(0, 3)$, so its equation is $3x + 4y = 12$.The shaded region lies below this boundary line, meaning the value of the expression is less than $12$.Thus the inequality is $3x + 4y < 12$.The graph is restricted to the positive side of both axes, so $x \ge 0$ and $y \ge 0$.Therefore, the inequalities represented are $3x + 4y < 12$, $x \ge 0$, $y \ge 0$.Answer:D. $3x + 4y < 12$, $x \ge 0$, $y \ge 0$