Given that sec2θ + tan2θ = 3
Where sec2θ = 1 + tan2θ
: 1 + tan2θ + tan2θ = 3
2tan2θ = 3 - 1
2tan2θ = 2
divide both sides by 2
tan2θ = 1
tanθ = √1
tanθ = 1
θ = tan−1 (1)
θ = 45º