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JAMB Mathematics 2021 Paper

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Question : 25

Total: 40

Find the probability that a number selected at random from 41 to 56 is a multiple of 9

$\frac{1}{8}$
$\frac{2}{15}$
$\frac{3}{16}$
$\frac{7}{8}$

Solution:

Concept:

Probability is the ratio of favourable outcomes to total possible outcomes.

Explanation:

The numbers from 41 to 56 inclusive are:

41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56

Total possible outcomes

= 16

Multiples of 9 in this range are

45

and

54

.

Favourable outcomes

= 2

P(\text{multiple of } 9) = \frac{\text{favourable outcomes}}{\text{total outcomes}} = \frac{2}{16}

Simplify:

\frac{2}{16} = \frac{1}{8}

Answer:

\frac{1}{8}

Correct option: A.

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