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JAMB Mathematics 2021 Paper

Question : 2

Total: 40

Solution:

Concept:

Selection without order uses combinations.

Explanation:

The number of ways to select 2 students from 5 is

^{5}C_{2}

Use the combination formula:

^{5}C_{2} = \frac{5!}{(5-2)!2!}

Simplify the factorials:

\frac{5!}{3!2!} = \frac{5 \times 4 \times 3!}{3! \times 2 \times 1}

Cancel

3!

\frac{5 \times 4}{2 \times 1} = \frac{20}{2} = 10

Thus, there are 10 possible selections.

Answer:

B. 10 ways

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