Concept:Use the difference of two squares: x2−y2=(x+y)(x−y).Explanation:Let x=4a+3 and y=3a−2.Then (4a+3)2−(3a−2)2=x2−y2.Factorise using the difference of two squares:(x+y)(x−y)=[(4a+3)+(3a−2)][(4a+3)−(3a−2)]Simplify the first bracket:(4a+3)+(3a−2)=7a+1Simplify the second bracket:(4a+3)−(3a−2)=4a+3−3a+2=a+5Therefore, the factorised form is:(7a+1)(a+5)Answer:(a+5)(7a+1) which is option C.