In this fiqure, PQ = PR = PS and SRT = 68o. Find QPS
Since PQRS is quadrilateral
2y + 2x + QPS = 360o
i.e. (y + x) + QPS = 360o
QPS = 360o - 2 (y + x)
But x + y + 68o = 180o
There; x + y = 180o - 68o = 112o
QPS = 360 - 2(112o)
= 360o - 224 = 136o