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JAMB Mathematics 2019 Paper

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Question : 59

Total: 73

Find the probability that a number selected at random from 21 to 34 is a multiple of 3

$\frac{3}{11}$
$\frac{2}{9}$
$\frac{5}{14}$
$\frac{5}{13}$

Solution:

Concept:

Probability is the ratio of favourable outcomes to the total number of possible outcomes.

Explanation:

The numbers from 21 to 34 are:

S = \{21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34\}

Total outcomes:

n(S) = 14

Multiples of 3 in this range are:

\{21, 24, 27, 30, 33\}

Favourable outcomes:

n(E) = 5

Probability

= \frac{n(E)}{n(S)} = \frac{5}{14}

Answer:

\frac{5}{14}

(Option C)

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