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JAMB Mathematics 2019 Paper

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Question : 54

Total: 73

A binary operation Δ is defined by a Δ b = a + 3b + 2.

Find (3 Δ 2) Δ 5

35
59
28
87

Solution:

Concept:

Evaluate the binary operation step by step from the inner bracket outward.

Explanation:

First compute

3 \Delta 2

using

a \Delta b = a + 3b + 2

.

3 \Delta 2 = 3 + 3(2) + 2 = 11

.

Now replace the bracket with

11

, so

(3 \Delta 2) \Delta 5 = 11 \Delta 5

.

Then evaluate

11 \Delta 5 = 11 + 3(5) + 2

.

= 11 + 15 + 2 = 28

.

Answer:

28

(Option C).

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