JAMB Mathematics 2019 Paper

Concept:Solving a linear inequality by clearing fractions and isolating $x$.Explanation:Start with the given inequality: $$\frac{4x-6}{3} \leq \frac{3+2x}{2}$$ Multiply both sides by the common denominator $6$ to remove the fractions. This gives: $$2(4x-6) \leq 3(3+2x)$$ Expand both sides. $$8x - 12 \leq 9 + 6x$$ Collect like terms by subtracting $6x$ from both sides. $$8x - 6x \leq 9 + 12$$ Simplify each side. $$2x \leq 21$$ Divide both sides by $2$. Since we divide by a positive number, the inequality sign stays the same. $$x \leq \frac{21}{2}$$Answer:$x \leq \frac{21}{2}$ Correct option: B.