ddx[\log(4x3−2x)] ... (1)
Let u = 4x3 - 2x.
ddx(\log(4x3−2x))=(ddu)(dudx)
ddu(\logu) = 1u
dudx=12x2−2
∴ddx[\log(4x3−2x)]=12x2−2u
= 12x2−24x3−2x