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JAMB Mathematics 2018 Paper

Question : 7

Total: 62

\frac{3}{4}

\frac{1}{3}

(21 - t) = 11

Solution:

Concept:

Solve a linear equation with fractions by eliminating the denominators.

Explanation:

Start with the equation:

\frac{3}{4}t + \frac{1}{3}(21 - t) = 11

Find the LCM of the denominators

4

and

3

, which is

12

Multiply every term of the equation by

12

12 \times \frac{3}{4}t + 12 \times \frac{1}{3}(21 - t) = 12 \times 11

Simplify each term:

9t + 4(21 - t) = 132

Expand the bracket:

9t + 84 - 4t = 132

Collect like terms:

5t + 84 = 132

Subtract

84

from both sides:

5t = 48

Divide both sides by

5

t = \frac{48}{5} = 9\frac{3}{5}

Answer:

t = 9\frac{3}{5}

, so the correct option is D.

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