Concept:The determinant of a 3×3 matrix is found by expanding along a row or column using minors and alternating signs.Explanation:Given N=36−25−32−4−51, we expand along the first row with signs +, −, +.∣N∣=3−32−51−56−2−51+(−4)6−2−32.First minor: 3[(−3)(1)−(−5)(2)]=3(−3+10)=3(7)=21.Second minor: −5[(6)(1)−(−5)(−2)]=−5(6−10)=−5(−4)=20.Third minor: (−4)[(6)(2)−(−3)(−2)]=−4(12−6)=−4(6)=−24.Add the three results:∣N∣=21+20−24=17.Answer:∣N∣=17, so the correct option is C. 17.