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JAMB Mathematics 2018 Paper

Question : 19

Total: 62

Solution:

Concept:

For an even total frequency, the median is the average of the

\frac{N}{2}

th and

\left(\frac{N}{2}+1\right)

th terms.

Explanation:

Total frequency:

N = 1 + 2 + 7 + 5 + 4 + 3 = 22

Since

N

is even, the median lies between the 11th and 12th terms.

Cumulative frequencies are:

1, 3, 10, 15, 19, 22

The 11th and 12th terms both fall on the mark

4

So the median is

\frac{4 + 4}{2} = \frac{8}{2} = 4

Answer:

D. 4

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