Test Index

JAMB Mathematics 2018 Paper

Question : 15

Total: 62

Make T the subject of the relation.

Solution:

Concept:

Use inverse operations to isolate

T

: remove the cube root, then clear the fraction before rearranging.

Explanation:

Begin with the relation:

P = \left(\frac{Q(R-T)}{15}\right)^{\frac{1}{3}}

Cube both sides to eliminate the cube root:

P^3 = \frac{Q(R-T)}{15}

Multiply both sides by

15

15P^3 = Q(R-T)

Divide both sides by

Q

\frac{15P^3}{Q} = R - T

Rearrange to make

T

the subject:

T = R - \frac{15P^3}{Q}

Answer:

T = R - \frac{15P^3}{Q}

This corresponds to Option C.

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