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JAMB Mathematics 2017 Paper

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Question : 40

Total: 44

Simplify (3√64a³)

^{-1}

4a
$\frac{1}{8a}$
8a
$\frac{1}{4a}$

Solution:

Concept:

A negative exponent indicates the reciprocal of the expression.

Explanation:

Write the expression as

\left(\sqrt[3]{64a^3}\right)^{-1}

.

Apply the negative exponent rule:

\left(\sqrt[3]{64a^3}\right)^{-1} = \frac{1}{\sqrt[3]{64a^3}}

.

Evaluate the cube root:

\sqrt[3]{64a^3} = 4a

.

Therefore,

\frac{1}{\sqrt[3]{64a^3}} = \frac{1}{4a}

.

Answer:

\frac{1}{4a}

Option D.

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