JAMB Mathematics 2017 Paper

Concept:Arranging letters with repeated items requires dividing by the factorial of each repeated letter count.Explanation:The word MACICITA has $8$ letters in total, so without restrictions there are $8!$ arrangements.The repeated letters are: A appears $2$ times, C appears $2$ times, and I appears $2$ times.Dividing by the factorials of these repeated counts removes identical arrangements.Therefore, the number of distinct arrangements is:$$\frac{8!}{2! \times 2! \times 2!} = \frac{8!}{2! 2! 2!}$$Answer:C. $\displaystyle \frac{8!}{2! 2! 2!}$