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JAMB Mathematics 2017 Paper

Question : 23

Total: 44

Divide 4x3 - 3x + 1 by 2x - 1

Solution:

Concept:

Use polynomial long division to divide

\mathrm{4}x^3 - 3x + 1

\mathrm{2}x - 1

Explanation:

Rewrite the dividend with a zero placeholder for the missing

x^2

term:

4x^3 + 0x^2 - 3x + 1

Divide

4x^3

2x

to get

2x^2

Multiply:

2x^2(2x - 1) = 4x^3 - 2x^2

Subtract:

(4x^3 + 0x^2 - 3x + 1) - (4x^3 - 2x^2) = 2x^2 - 3x + 1

Divide

2x^2

2x

to get

x

Multiply:

x(2x - 1) = 2x^2 - x

Subtract:

(2x^2 - 3x + 1) - (2x^2 - x) = -2x + 1

Divide

-2x

2x

to get

-1

Multiply:

-1(2x - 1) = -2x + 1

Subtract to get remainder

0

Therefore, the quotient is

2x^2 + x - 1

Answer:

Option D:

2x^2 + x - 1

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