Test Index

JAMB Mathematics 2017 Paper

© africaexams.com

Question : 20

Total: 44

Simplify 4

\sqrt{27}

\sqrt{12}

\sqrt{75}

7
− 7
− 7 $\sqrt{3}$
7 $\sqrt{3}$

Solution:

Concept:

Simplify each surd by factoring out perfect squares, then combine like terms.

Explanation:

First, express each radical in terms of

\sqrt{3}

.

4\sqrt{27} = 4\sqrt{9 \times 3} = 4 \times 3\sqrt{3} = 12\sqrt{3}

5\sqrt{12} = 5\sqrt{4 \times 3} = 5 \times 2\sqrt{3} = 10\sqrt{3}

-3\sqrt{75} = -3\sqrt{25 \times 3} = -3 \times 5\sqrt{3} = -15\sqrt{3}

Now add the like terms:

12\sqrt{3} + 10\sqrt{3} - 15\sqrt{3} = (12 + 10 - 15)\sqrt{3} = 7\sqrt{3}

Answer:

7\sqrt{3}

© africaexams.com

Go to Question:

Prev Question

Next Question