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JAMB Mathematics 2016 Paper

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Question : 24

Total: 50

Evaluate

\frac{ \frac{27^{1}}{3} - \frac{8^{2}}{3} }{ \frac{16^{2}}{4} \times 2 }

$\frac{23}{5}$
- $\frac{23}{5}$
- $\frac{1}{8}$
$\frac{21}{7}$

Solution:

Concept:

Simplify fractional powers first, then combine the numerator and denominator.

Explanation:

Evaluate each fractional power separately.

27^{\frac{1}{3}} = 3

because

3^3 = 27

.

8^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 2^2 = 4

.

16^{\frac{2}{4}} = 16^{\frac{1}{2}} = 4

.

Substitute these values into the expression:

\frac{27^{\frac{1}{3}} - 8^{\frac{2}{3}}}{16^{\frac{2}{4}} \times 2} = \frac{3 - 4}{4 \times 2}

= \frac{-1}{8}

Answer:

\frac{-1}{8}

, which is option C.

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