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JAMB Mathematics 2016 Paper

Question : 20

Total: 50

Solution:

Concept:

The complement of

P

is the set of elements in the universal set

U

that are not in

P

Explanation:

First, list the universal set.

U = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14\}

Next, list the even numbers from

1

14

P = \{2, 4, 6, 8, 10, 12, 14\}

Remove the elements of

P

from

U

P' = U \setminus P

P' = \{1, 3, 5, 7, 9, 11, 13\}

Answer:

The complement of

P

\{1, 3, 5, 7, 9, 11, 13\}

, which is option C.

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