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JAMB Mathematics 2015 Paper

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Question : 25

Total: 61

One bag contain 3 blue and 5 red balls, another bag contain 2 blue and 4 red balls respectively. One ball is drawn for each bag. What is the probability both balls are blue

$\frac{2}{15}$
$\frac{3}{24}$
$\frac{3}{21}$
$\frac{3}{28}$

Solution:

Concept:

The two draws are independent events.

So, multiply their individual probabilities.

Explanation:

First bag:

3

blue and

5

red balls, so total balls

= 3 + 5 = 8

.

Probability of blue from first bag

= \frac{3}{8}

.

Second bag:

2

blue and

4

red balls, so total balls

= 2 + 4 = 6

.

Probability of blue from second bag

= \frac{2}{6}

.

Therefore, probability both balls are blue:

\frac{3}{8} \times \frac{2}{6} = \frac{6}{48} = \frac{3}{24}

.

Answer:

Option B:

\frac{3}{24}

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