y - 4x + 3 = 0When y = 0, 0 - 4x + 3 = 0Then -4x = -3x = 3/4So the line cuts the x-axis at point (3/4, 0).When x = 0, y - 4(0) + 3 = 0Then y + 3 = 0y = -3So the line cuts the y-axis at the point (0, -3)Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;[12(x1+x2),12(y1+y2)][12(34+0),12(0+−3)][12(34),12(−3)][38,−32]
