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JAMB Mathematics 2014 Paper

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Question : 24

Total: 47

A cylindrical tank has a capacity of 6160m³. What is the depth of the tank if the radius of its base is 28cm?

8.0m
7.5m
5.0m
2.5m

Solution:

Concept:

The volume of a cylinder is found using

V = \pi r^{2} h

.

Explanation:

Given:

V = 6160\,\text{m}^{3}

and the intended radius from the options is

r = 28\,\text{m}

.

Using

\pi = \frac{22}{7}

:

6160 = \frac{22}{7} \times 28 \times 28 \times h

Simplify the right-hand side:

\frac{22}{7} \times 28 \times 28 = 22 \times 4 \times 28 = 2464

So,

6160 = 2464h

Therefore,

h = \frac{6160}{2464} = 2.5\,\text{m}

Answer:

D.

2.5\,\text{m}

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