Given P(2, -3) and Q(-5, 1)
Midpoint = (,)
= (,−1)
Slope of the line PQ =
= −
The slope of the perpendicular line to PQ =
=
The equation of the perpendicular line: y=x+b
Using a point on the line (in this case, the midpoint) to find the value of b (the intercept).
−1=()()+b
−1+==b
∴ The equation of the perpendicular bisector of the line PQ is y=x+
≡8y=14x+13implies8y−14x−13=0