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JAMB Mathematics 2013 Paper

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Question : 31

Total: 47

A basket contains 9 apples, 8 bananas and 7 oranges. A fruit is picked from the basket, find the probability that it is neither an apple nor an orange.

$rac{3}{8}$
$rac{1}{3}$
$rac{7}{24}$
$rac{2}{3}$

Solution:

Concept:

Probability is the ratio of favourable outcomes to the total number of possible outcomes.

Explanation:

Total fruits in the basket:

9 + 8 + 7 = 24

.

A fruit that is neither an apple nor an orange must be a banana.

Number of bananas

= 8

.

Required probability

= \frac{8}{24} = \frac{1}{3}

.

Answer:

\frac{1}{3}

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