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JAMB Mathematics 2011 Paper

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Question : 35

Total: 46

Evaluate

\int\limits_{0}^{1}

(3 - 2x)dx

33m
5
2
6

Solution:

Concept:

A definite integral is solved by finding the antiderivative and then applying the limits of integration.

Explanation:

Find the antiderivative of

3 - 2x

.

\int (3 - 2x)\,dx = 3x - x^2

Evaluate from

0

to

1

:

[3x - x^2]_{0}^{1} = (3(1) - 1^2) - (3(0) - 0^2)

= (3 - 1) - (0 - 0) = 2 - 0 = 2

Answer:

The value of the integral is

2

, which is option C.

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