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JAMB Mathematics 2011 Paper

Question : 26

Total: 46

Solution:

Concept:

The tank can now hold the volume of water equal to its total capacity minus the volume occupied by the solid cube.

Explanation:

Volume of the rectangular tank

= l \times b \times h

V_{\text{tank}} = 3 \times 4 \times 5 = 60 \, \text{cm}^3

Volume of the solid metal cube

= s^3

V_{\text{cube}} = 3^3 = 27 \, \text{cm}^3

Remaining volume for water

= V_{\text{tank}} - V_{\text{cube}}

= 60 - 27 = 33 \, \text{cm}^3

Answer:

33 \, \text{cm}^3

(Option B).

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