Concept:Evaluate a 3×3 determinant by expanding along the first row.Explanation:Use the first row and apply the sign pattern +,−,+.42−1231−1−13=431−13−22−1−13+(−1)2−131For a 2×2 matrix, acbd=ad−bc.So compute each minor:=4(3⋅3−(−1)(1))−2(2⋅3−(−1)(−1))+(−1)(2⋅1−3(−1))=4(10)−2(5)+(−1)(5)=40−10−5=25Answer:25, which is Option A.