JAMB Mathematics 2011 Paper

Concept:A linear inequality is solved by expanding brackets, collecting like terms, and isolating the variable while keeping the inequality direction unchanged because we divide by a positive number.Explanation:Expand both sides:$-6(x+3) \leq 4(x-2)$ becomes $-6x - 18 \leq 4x - 8$.Collect like terms by moving $x$-terms to one side and constants to the other:$-18 + 8 \leq 4x + 6x$.Simplify:$-10 \leq 10x$.Rewrite the inequality with $x$ on the left:$10x \geq -10$.Divide both sides by $10$:$x \geq -1$.Answer:$x \geq -1$, so the correct option is B.