A committee of 2 women and 3 men can be chosen from 6 men and 5 women, in 5C2 x 6C3 ways = 5!(5−2)!2!×6!(6−3)!3! = 5!3!2!×6!3×3! = 5×4×3!3!×2!×6×5×4×3!3!×3! = 5×41×2×6×5×41×2×3 = 10 x 6×206 = 200
