Concept:Use the expansion of a 3×3 determinant along the first row.Explanation:For a matrix adgbehcfithe determinant is a(ei−fh)−b(di−fg)+c(dh−eg).Here, a=2, b=0, c=5, d=4, e=6, f=3, g=8, h=9, and i=1.First minor: ei−fh=(6)(1)−(3)(9)=6−27=−21.So the first term is 2(−21)=−42.The second term is zero because b=0.Second minor: dh−eg=(4)(9)−(6)(8)=36−48=−12.So the third term is 5(−12)=−60.Therefore, the determinant is −42−60=−102.Answer:The determinant is −102, which is option C.