JAMB Mathematics 2010 Paper

Concept:Solving a compound inequality by splitting it into two separate inequalities.Explanation:Write $-6 \leq 4 - 2x$ and $4 - 2x < 5 - x$.Solve the first part:$-6 \leq 4 - 2x$Subtract $4$ from both sides:$-10 \leq -2x$Divide both sides by $-2$ and reverse the inequality sign:$5 \geq x$This means $x \leq 5$.Now solve the second part:$4 - 2x < 5 - x$Add $x$ to both sides and subtract $4$:$-x < 1$Divide both sides by $-1$ and reverse the inequality sign:$x > -1$This means $-1 < x$.Combine both results:$-1 < x \leq 5$Answer:B. $-1 < x \leq 5$