Concept:An arithmetic progression (AP) has terms written as a+(n−1)d, where a is the first term and d is the common difference.Explanation:The 3rd term is a+2d=−9.The 7th term is a+6d=−29.Subtract the first equation from the second: (a+6d)−(a+2d)=−29−(−9).This gives 4d=−20, so d=−5.Substitute d=−5 into a+2d=−9: a+2(−5)=−9.So a−10=−9, hence a=1.The 10th term is a+9d=1+9(−5)=1−45=−44.Answer:The 10th term is −44, which is option A.