JAMB Mathematics 2010 Paper

Concept:In a right-angled triangle, the two smaller sides meet at the right angle.These two sides serve as the base and the height of the triangle.Explanation:The two smaller sides are $4\text{ cm}$ and $5\text{ cm}$.Take the base $= 4\text{ cm}$ and the height $= 5\text{ cm}$.The formula for the area of a triangle is $\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$.Substitute the given values into the formula.$\text{Area} = \frac{1}{2} \times 4 \times 5$.First multiply the lengths: $4 \times 5 = 20$.Then multiply by $\frac{1}{2}$: $\text{Area} = \frac{1}{2} \times 20 = 10$.Therefore, the area of the right-angled triangle is $10\text{ cm}^2$.Answer:$10\text{ cm}^2$