Let n be a natural number.Consider the expression:n2+n+3=n(n+1)+3The product n(n+1) is the product of two consecutive integers.For any two consecutive integers, one of them must be even. Therefore, their product has a factor of 2, so:n(n+1) is evenSince an even number plus 3 is always odd, it follows that:n(n+1)+3 is oddThus:n2+n+3 is oddSo the claim is true for every natural number n.