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JAMB Chemistry 2024 Paper

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Question : 84

Total: 138

If 11.0g of a gas occupies 5.6 dm

^3

at s.t.p., calculate its vapour density (1 mole of a gas occupies 22.4 dm

^3

).

22
44
66
88

Solution:

If 11.0g occupies 5.6 dm $^3$

x will occupy 22.4 dm $^3$

x = $\;\frac{11\times 22.4}{5.6}$

x = 44g

But Molecular mass = 2 x Vapour density

44 = 2 x Vapour density

Vapour density = $\;\frac{44}{2}$ = 22

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