Firstly, Ag+ + e− → Ag
1 mole = 1 F = 96,500C x 1 e−
⇒ If 96,500C liberates 108g of Ag
x will liberate 16g of Ag
x = = 14,296.30 C
i.e The quantity of electricity that would liberate 16g of Ag which is also the same quantity that will liberate X of Mg = 14,296.30 C
Thus, Mg2+ + 2e− → Mg
If 2e− X 96,500C liberates 24g of Mg
14,296.30C will liberate Xg of Mg
By simple proportion, X =
= 1.78g