Concept:After
n half-lives, the fraction of a radioactive substance remaining is
(21)n.
Explanation:The total time elapsed is
10 minutes.
The half-life of the substance is
2 minutes.
So the number of half-lives that have passed is:
n=210=5The fraction remaining after
5 half-lives is:
(21)5=321Since the original mass is
1 g, the residual mass is:
321 gIf the question strictly asks for the fraction disintegrated, it would be:
1−321=3231However,
3231 is not among the options given.
Therefore, among the options provided,
321 is the fraction remaining.
Answer:Option D:
321 (fraction remaining).