1 mole of CaCO3 = 100g or 6.02 X 1023
liberated 1 mole of CO2 or 44g or 6.02 X 1023
:100g = 6.02 X 1023
10g of CaCO3 = x
cross multiply
[10g X 6.02 X 1023] / 100g = x
⇒ x = 6.02 X 1022
Since
6.02 X 1023 of CaCO3 liberated 6.02 X 1023 of CO2
⇒ 6.02 X 1022 of CaCO3 will liberate 6.02 X 1022 of CO2
