Concept:Number the ethane carbon chain to give the lowest locant set, then list substituents alphabetically.
Explanation:The compound is
CF3CHBrCl, which is a two-carbon ethane chain.
Carbon 1 has three fluorine atoms, and carbon 2 has bromine and chlorine atoms.
Numbering from the
CF3 end gives locants:
1,1,1 for fluorine and
2,2 for bromine and chlorine.
Numbering from the other end would give
1,1 for bromine/chlorine and
2,2,2 for fluorine, which is a higher locant set.
So the correct numbering is from the
CF3 end.
Alphabetically: bromo before chloro before fluoro.
Answer:2-bromo-2-chloro-1,1,1-trifluoroethane
Correct option: B