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JAMB Chemistry 2019 Paper

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Question : 69

Total: 80

The emission of two successive beta particles from the nucleus

^{32}_{15}\mathrm{P}

will produce

$^{30}_{14}$ Si
$^{32}_{13}$ Al
$^{32}_{17}$ Cl
$^{32}_{16}$ S

Solution:

$^{32}_{15}$ P $\to$ 2 $^{0}_{-1}$ e + $^{a}_{b}$ X

32 = 2(0) + a

a = 32

15 = 2(-1) + b

b = 15 + 2

b = 17

$\therefore$ $^{a}_{b}$ X = $^{32}_{17}$ Cl

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